February 17, 2004

Let's assume that when you have one kid that they're sick 10% of the time. Given that you might think that if you have two kids that one of them would be sick 20% of the time (actually it would be 19% of the time, but we're close enough for government work or meaningless weblogs). You might further assume that three kids would mean that one was sick 30% of the time (or 27.1% if you want to be anal) and that four kids would equal 40% (okay fine, fine, 34.4% of the time). But if you thought that you would be wrong, the progression isn't arithmetic ... it's geometric...

If one kid is sick 10% of the time, then if you have two kids one of them is sick 30% of the time and with three kids it will be 70% of the time, by the time you hit four kids you're well over 100%. I'm too tired to work through all the probabilities of two, three or four kids being sick at the same time but that's where I was this last weekend. Toss in a sick wife and the scene is complete. Okay, actually no, I forgot helping my friend with critiquing his two IRON DM entries.

The long and the short of it is that I didn't get the next Xenogenic NPC up. He's mostly done, but I ran out of time. However I should have him up in the next day or two depending on whether I have to spend any extra time with my 9 to 5 job. Anyhow, while you're waiting head on over to E-Bay and pick up your own Navy F-18 Hornet.

Carpe Diem Quam Minimum Credula Postero
Ross

Posted by direkobold at February 17, 2004 11:09 PM
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